Hangout #2 : Better 'cos Jaws made it.

[polobunny]

I hate you all!
I WISH YOU ALL DIED
sniff

Edit: That exam doesn't look very hard, I guess i could do it if it wasn't of that language barrier.

[Evans]

I hate you all!
I WISH YOU ALL DIED
sniff

Edit: That exam doesn't look very hard, I guess i could do it if it wasn't of that language barrier.

Keep on wishing. And working on that PS thing.

[Evans]

OMG! Integrals! Yay, I love those!

[pkt-zer0]

Edit: That exam doesn't look very hard, I guess i could do it if it wasn't of that language barrier.

I couldn't really think of a way to solve 5/a. Help would be appreciated.

[Evans]

I couldn't really think of a way to solve 5/a. Help would be appreciated.

If you tell me WTH (ch2x) is, I'll get on it.

[pkt-zer0]

If you tell me WTH (ch2x) is, I'll get on it.

ch(x) is hyperbolic cosine, equals (e^x + e^-x)/2.
More precisely: http://mathworld.wolfram.com/HyperbolicCosine.html

[Evans]

ch(x) is hyperbolic cosine, equals (e^x + e^-x)/2.
More precisely: http://mathworld.wolfram.com/HyperbolicCosine.html

I see.

*checks it out...*

[nosebluntsmoker]

Shit.. I haven't done calculus since I took calc101 in grade 12. Yeah.. I <i>was</i> smart like that..

[Evans]

So, the way I see it, this should be quick enough.

Derivative of (anything)^n = n(anything)^n-1

So, this will look like: (1/x)[(yak yak)^((1/x)-1)].

Hence, when x=0, that whole thing is devided by 0.

Answer, the limit, when x => 0 is infinity.


Unless I'm mistaken, which is likely. Been about 3 years.

[nosebluntsmoker]

I don't have acrobat..

[Skinner8]

http://forums.emuparadise.org/showthread.php?t=27935

Best. Ever.

[nosebluntsmoker]

No, I'm the best. Jesus said so.

[Springer]

Evening people.

[nosebluntsmoker]

Afternoon Springer.

[Evans]

No, I'm the best. Jesus said so.

Jesus talks too much.