Indeed... :)
That's a little something our Numerical Analysis teacher told us to solve a little while ago (along with a few others)... I wanted to see if anyone here got it right... :P
Printable View
Indeed... :)
That's a little something our Numerical Analysis teacher told us to solve a little while ago (along with a few others)... I wanted to see if anyone here got it right... :P
ahhhhhhhhhhhhh too much math to comprehend!!
I got losed around the point you guys started doing log(). We haven't done that in my math class yet...
well i for one have absolutely no idea what is going on here. i was about to spew out my knowledge of multiplication properties to end this early, then i saw odd looking equations popping up, each more strange than the last. i am lost and have been lost since before i was halfway done with Ace's first post. and i have math tomorrow. good luck to whoever gets it.
how can you add something to one side of an equation without adding it to the other side@_@?Quote:
Originally posted by vagrantcharly
Now, what Ace posted reminded me of this:
1/2 > 1/4
log(1/2) > log(1/4)
log(1/2) > log((1/2)^2)
log(1/2) > 2*log(1/2)
1 > 2
Anyone...? :)
i dunno anything about logs though:P
He didn't add anything, LoL.
He just took log on both sides :P.
Also, Urn, when logs are generally taken, they're assumed to be to the base, e, that is, natural or napieran logarithms, commonly, we use base 10 logarithms for all our calculations, and in both those cases, the above result is false :D
ooook.as long as logs aren't there in the Xth boards,i don't mind.but they give you the log tables,don't they?i mean,you don't have to memorise it.......do you:S?
LoL ofcourse not, they always give you the log tables. Only in the IIT entrances you're not allowed log tables, you have to use the napieran formula and there's another algorithm, to calculate the logs.. Or they'll give you the log you need to use in the calculation, as well as the anti log.
Eek, for any purpose I've had to use logs, it is either acceptable to leave it in log form or you can use a calculator for it.
That was acheived with the logarithm rules
ln(a^b) = b*ln(a)
ALL THESE NUMBERS! Shit, I feel like a blonde stuck in a lost-pink shoes situation! *wonders what it would feel like since she's not a blonde and HATES pink!*
bottom line-I SUCK AT MATHS!
HEEEEEEEEEYYYYYYY, MasJ !!
ln - log with base=e
lg - log with base=10
just log(x) is a wrong notation.
Thats common math rules.
At least in my country :)
In what I've learned log(x) is assumed to be base 10, just as ln(x) is base e, guess it's different here. Just out of curiosity what math are you guys taking? I'm in calc 2 right now and it pretty much sucks.
2xaenn: what do u mean?
Also base 10 here if no other base has been specified.Quote:
Originally posted by Xaenn
In what I've learned log(x) is assumed to be base 10, just as ln(x) is base e, guess it's different here. Just out of curiosity what math are you guys taking? I'm in calc 2 right now and it pretty much sucks.
Advanced Math here, highest math available at my school ><
why do i get the feeling that altavista won't be able to translate that:wacko:?Quote:
Originally posted by MasJ
LoL ofcourse not, they always give you the log tables. Only in the IIT entrances you're not allowed log tables, you have to use the napieran formula and there's another algorithm, to calculate the logs.. Or they'll give you the log you need to use in the calculation, as well as the anti log.